Chemistry help needed.. Would be appreciated?

Molar mass of = 14 + 1×28 + 27 + 32.1×2 + 16×20 = 453.2 g/mol

Number of moles of NH₄Al(SO₄)₂•12H₂O = (6.022 × 10²³)/(6.022 × 10²³) = 1 mol

Mass of NH₄Al(SO₄)₂•12H₂O = 453.2 × 1 = 453.2 g

You do have a printed periodic table, right? You can get the information at http://www.chemicalelements.com/index.html but you really need your own printed copy to carry with you. It will be a primary reference for everything you do.

Look up atomic mass for each element.
N - 14.00674
H - 1.00794
Al - 26.981539
S - 32.066
O - 15.9994

Multiply each by the number of times it is used and add them up. That is the molar mass of your compound, the mass of 6.02 x 10^23 molecules.