you prepared 200ml of an HCL solution and are standardizing with 25ml of a .1250 M Na2CO3. you use all 25ml. what is the HCL concentration?
回答 (1)
2016-02-22 8:15 am
Na₂CO₃ + 2HCl → 2NaCl + H₂O + CO₂
1 mole of Na₂CO₃ reacts with 2 moles of HCl.
No. of moles of Na₂CO₃ = (0.125 mol/L) × (25/1000 L) = 0.003125 mol
No. of moles of HCl = (0.003125 × 2) = 0.00625 mol
Molarity of HCl = (0.00625 mol) / (200/1000 L) = 0.03125 M
1 mole of Na₂CO₃ reacts with 2 moles of HCl.
No. of moles of Na₂CO₃ = (0.125 mol/L) × (25/1000 L) = 0.003125 mol
No. of moles of HCl = (0.003125 × 2) = 0.00625 mol
Molarity of HCl = (0.00625 mol) / (200/1000 L) = 0.03125 M
收錄日期: 2021-04-18 14:29:14
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