a student transfers 25ml of a 5.0x10-3M NaOH solution into a 500 ml volumetric flask and fills with deionized water What is the molarity?
回答 (1)
2016-02-22 8:20 am
Method 1 :
No. of moles of NaOH transfer = (5.0 × 10⁻³ mol/L) × (25/1000 L) = 1.25 × 10⁻⁴ mol
Molarity after dilution = (1.25 × 10⁻⁴ mol) / (500/1000) = 2.5 × 10⁻⁴ M
Method 2 :
M₁ V₁ = M₂ V₂
(5.0 × 10⁻³ mol/L) × (25 ml) = M₂ × (500 ml)
Molarity after dilution, M₂ = 2.5 × 10⁻⁴ M
No. of moles of NaOH transfer = (5.0 × 10⁻³ mol/L) × (25/1000 L) = 1.25 × 10⁻⁴ mol
Molarity after dilution = (1.25 × 10⁻⁴ mol) / (500/1000) = 2.5 × 10⁻⁴ M
Method 2 :
M₁ V₁ = M₂ V₂
(5.0 × 10⁻³ mol/L) × (25 ml) = M₂ × (500 ml)
Molarity after dilution, M₂ = 2.5 × 10⁻⁴ M
收錄日期: 2021-04-18 14:38:55
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