Find the equation of the tangent to x² + y²=100 which passes through the point (6,8)?
回答 (2)
2016-02-20 3:38 pm
x^2 + y^2 = 100
2x * dx + 2y * dy = 0
x * dx + y * dy = 0
x = 6 , y = 8
6 * dx + 8 * dy = 0
3 * dx + 4 * dy = 0
4 * dy = -3 * dx
dy/dx = -3/4
y - 8 = (-3/4) * (x - 6)
4y - 32 = -3x + 18
4y = -3x + 50
y = (-3/4) * x + (25/2)
2x * dx + 2y * dy = 0
x * dx + y * dy = 0
x = 6 , y = 8
6 * dx + 8 * dy = 0
3 * dx + 4 * dy = 0
4 * dy = -3 * dx
dy/dx = -3/4
y - 8 = (-3/4) * (x - 6)
4y - 32 = -3x + 18
4y = -3x + 50
y = (-3/4) * x + (25/2)
收錄日期: 2021-04-18 14:34:37
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