更新1:
Please simplify the expression. Thank you!
Using the distributive property of multiplication over addition to factor. ab+ac=a(b+c) 47 X 99 + 47?
回答 (3)
2016-02-20 1:45 pm
47 × 99 + 47
= 47 × 99 + 47 × 1
= 47 × (99 + 1)
= 47 × 100
= 4700
= 47 × 99 + 47 × 1
= 47 × (99 + 1)
= 47 × 100
= 4700
2016-02-20 1:43 pm
We can think of this as:
a = 47
b = 99
c = 1
In other words, think of 47 in the original expression as 47 × 1:
47 × 99 + 47 × 1
Now factor the common 47 to the front:
= 47(99 + 1)
Simplify the part in parentheses:
= 47(100)
Multiply the two numbers to get the final result:
= 4700
a = 47
b = 99
c = 1
In other words, think of 47 in the original expression as 47 × 1:
47 × 99 + 47 × 1
Now factor the common 47 to the front:
= 47(99 + 1)
Simplify the part in parentheses:
= 47(100)
Multiply the two numbers to get the final result:
= 4700
2016-02-20 1:40 pm
47 x (99+47)
= (47)(99) + (47)(47)
= 4653+ 2209
= 6862
= (47)(99) + (47)(47)
= 4653+ 2209
= 6862
收錄日期: 2021-04-18 14:27:47
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160220053827AAnc1zW