x/2 + y/3 = 2 , x + 2y = 8 Whats the Value of X and Y ?

(x/2) + (y/3) = 2 ...... [1]
x + 2y = 8 ...... [2]

From [1] :
(3x/6) + (2y/6) = 2
(3x + 2y)/6 = 2
3x + 2y = 12 ...... [3]

[2] * 3 :
3x + 6y = 24 ...... [4]

[4] - [3] :
4y = 12
y = 3

Put y = 3 into [1] :
x + 2(3) = 8
x = 2

Hence, x = 2 and y = 3

3x+ 2y = 12
-3x - 6y = - 24_____ADD

-4y = - 12
y = 3

3x = 6
x = 2

x = 2 , y = 3

x/2+ y/3 = 2
multiply both sides by 6
3x+2y =12 ----(1)
x+2y = 8 -----(2)

subtract (2) from (1)
2x = 4
x= 2

substitute x=2 into equation (2)
2+2y = 8
2y = 6
y=3

x=2
y=3

X/2 + y/3 = 2 , ................(1)

x + 2y = 8 ......................(2)

Multiply (1) by 6

3x + 2y = 12 .............(3)

Subtract (2) from (3)

2x = 4

x = 2

Put this in (2)

2 + 2y = 8

2y = 6

y = 3

solution ( 2, 3)