What is the length of the side of a square whose diagonal is equal to 18cm?
回答 (5)
2016-02-20 9:41 am
Let y cm be the length of the side of the square.
Two adjacent sides and the diagonal form a right angle triangle.
By Pythagorean theorem :
y² + y² = 18²
2y² = 324
y² = 162
y = √162
y = 9√2
y ≈ 12.73
The length of the side of the square = 9√2 cm ≈ 12.73 cm
Two adjacent sides and the diagonal form a right angle triangle.
By Pythagorean theorem :
y² + y² = 18²
2y² = 324
y² = 162
y = √162
y = 9√2
y ≈ 12.73
The length of the side of the square = 9√2 cm ≈ 12.73 cm
2016-02-20 9:05 am
Let y cm be the length of the side of the square.
Two adjacent sides and the diagonal form a right angle triangle.
By Pythagorean theorem :
y² + y² = 18²
2y² = 324
y² = 162
y = √162
y = 9√2
y ≈ 12.73
The length of the side of the square = 9√2 cm ≈ 12.73 cm
Two adjacent sides and the diagonal form a right angle triangle.
By Pythagorean theorem :
y² + y² = 18²
2y² = 324
y² = 162
y = √162
y = 9√2
y ≈ 12.73
The length of the side of the square = 9√2 cm ≈ 12.73 cm
2016-02-20 9:06 am
a square of length of each side equal to length will hold relation of Pythagorus theorum since each side meets at a common point making 90 degree .
so a2 + a2 = 182 , that is 2a2 = 182 , or a2 = 18x 18 /2 cm2 , so a = sq root of 18x 18 /2 = 12.72792206 cm
so a2 + a2 = 182 , that is 2a2 = 182 , or a2 = 18x 18 /2 cm2 , so a = sq root of 18x 18 /2 = 12.72792206 cm
2016-02-20 9:04 am
12.73 cm
2016-02-20 9:02 am
Use the Pythagorean theorem:
s² + s² = 18²
2s² = 324
s² = 162
s = √162
s = √81√2
s = 9√2
s² + s² = 18²
2s² = 324
s² = 162
s = √162
s = √81√2
s = 9√2
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