balance _AgNO3+_BaCl2-->_AgCl+Ba(NO3)2.?
and how many grams of silver chloride are made from 5.0g silver nitrate assuming theres an excess of barium chloride
回答 (1)
2AgNO₃ + BaCl₂ → 2AgCl + Ba(NO₃)₂
Mole ratio AgNO₃ : AgCl = 2 : 2 = 1 : 1
Molar mass of AgNO₃ = 107.9 + 14 + 16×3 = 169.9 g/mol
Molar mass of AgCl = 107.9 + 35.5 = 143.4 g/mol
Number of moles of AgNO₃ = 5.0/169.9 mol
Number of moles of AgCl made = 5.0/169.9 mol
Mass of AgCl made = (5.0/169.9) × 143.4 = 4.2 g
收錄日期: 2021-04-18 14:33:33
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