what is the molar mass of a gas if 1.00g of the gas has a volume of 255mL at STP?
回答 (2)
2016-02-19 10:15 pm
mass, m = 1.00 g
molar mass, M = ? g/mol
volume, V = 255 mL = 0.255 L
temperature, T = 298 K
pressure, P = 1 atm
gas constant, R = 0.082 atm L / (mol K)
PV = nRT
PV = (m/M)RT
M = mRT/(PV)
Molar mass, M = 1.00 × 0.082 × 298 / (1 × 0.255) = 95.8
molar mass, M = ? g/mol
volume, V = 255 mL = 0.255 L
temperature, T = 298 K
pressure, P = 1 atm
gas constant, R = 0.082 atm L / (mol K)
PV = nRT
PV = (m/M)RT
M = mRT/(PV)
Molar mass, M = 1.00 × 0.082 × 298 / (1 × 0.255) = 95.8
2016-02-19 10:29 pm
1 mole occupies 24 dm^3 = 24,000 mL
Hence moles(gas) 255mL / 24,000 mL = 0.010625 moles.
Remember moles = mass/(g) / Mr.
mR = mass(g) / moles = 1 / 0.010625
Mr = 94.117
Mr (Krypton) = 84
So it could be Kypton. ?????
Hence moles(gas) 255mL / 24,000 mL = 0.010625 moles.
Remember moles = mass/(g) / Mr.
mR = mass(g) / moles = 1 / 0.010625
Mr = 94.117
Mr (Krypton) = 84
So it could be Kypton. ?????
收錄日期: 2021-04-18 14:29:34
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160219140729AAKiAgp