that has a downward acceleration of 2.8 m/s^2. The acceleration of gravity is 9.8 m/s^2. What is the magnitude of the force of the elevator floor on the person?
Answer in units of kN.
A person weighing 0.8 kN rides in an elevator?
2016-02-19 8:46 pm
回答 (3)
2016-02-19 8:58 pm
Take downward quantities as positive.
Mass of the person, m = (0.8×1000)/0.8 = 800/9.8 kg
Acceleration, a = 2.8 m/s²
F = ma
Net force acting on the person, F = (800/9.8) × 2.8 = 230 N = 0.23 N
Net force = Weight - (Force of the elevator floor on the person)
Magnitude of the force of the elevator floor on the person = 0.8 - 0.23 = 0.57 kN
Mass of the person, m = (0.8×1000)/0.8 = 800/9.8 kg
Acceleration, a = 2.8 m/s²
F = ma
Net force acting on the person, F = (800/9.8) × 2.8 = 230 N = 0.23 N
Net force = Weight - (Force of the elevator floor on the person)
Magnitude of the force of the elevator floor on the person = 0.8 - 0.23 = 0.57 kN
2016-02-19 9:35 pm
(800/g) x (g - 2.8) = 571.428N., or 0.57 kN.
2016-02-19 8:48 pm
mg - ma where g = 9.8 m/s^2 and a = the acceleration of the elevator
收錄日期: 2021-04-18 14:30:30
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