The doorway of the family room measures 6 feet by 3 feet. What is the length of the diagonal of the doorway?
回答 (4)
2016-02-19 8:46 pm
Let y feet be the length of the diagonal of the doorway.
The height, the width and the diagonal of the doorway form a right-angled triangle, and the diagonal is the hypotenuse.
By Pythagorean theorem :
y² = 6² + 3²
y² = 45
y = √45
y = 3√5
y ≈ 6.7 (to 1 decimal place)
The length of the diagonal of the doorway = 3√5 feet ≈ 6.7 feet
The height, the width and the diagonal of the doorway form a right-angled triangle, and the diagonal is the hypotenuse.
By Pythagorean theorem :
y² = 6² + 3²
y² = 45
y = √45
y = 3√5
y ≈ 6.7 (to 1 decimal place)
The length of the diagonal of the doorway = 3√5 feet ≈ 6.7 feet
2016-02-19 10:19 pm
d² = 6² + 3² = 45
d = 3 √5 ft
d = 3 √5 ft
2016-02-19 8:48 pm
The diagonal is the hypotinuse of a right triangle. Use the Pythagorean theorem to solve. 6^2. + 3^2. = C^2
36 + 9 = C^2
45 = C^2
C = square root of 45
36 + 9 = C^2
45 = C^2
C = square root of 45
收錄日期: 2021-04-18 14:28:22
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160219123918AA80bNA