0.1M鈉鹽溶夜NaA pH為11求水解常數? 還有Ka值?
回答 (1)
2016-02-17 3:17 pm
✔ 最佳答案
A⁻(aq) + H₂O(l) ⇌ HA(aq) + OH⁻(aq) .... Kh當平衡時：
pH = 11
pOH = 14 - 11 = 3
[OH⁻] = 10⁻³ = 0.001 M
[HA] = [OH⁻] = 0.001 M
[OH⁻] = 0.1 - 0.001 = 0.099 M
水解常數 Kh = [HA(aq)][OH⁻]/[ A⁻] = 0.001²/0.099 = 1.01 × 10⁻⁵
Ka = Kw/Kh = (1.00 × 10⁻¹⁴)/(1.01 × 10⁻⁵) = 9.9 × 10⁻¹⁰
收錄日期: 2021-04-18 14:27:30
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160217054922AA3aapY