(2分支3x+1二次方)-3分支1=9分支1?
回答 (1)
2016-02-14 9:59 am
[(3x + 1)²/2] - (1/3) = 1/9
兩邊同時乘以 18 :
{[(3x + 1)²/2] - (1/3)} × 18 = (1/9) × 18
9(3x + 1)² - 6 = 2
9(3x + 1)² = 8
(3x + 1)² = 8/9
3x + 1 = √(8/9) 或 3x + 1 = -√(8/9)
3x + 1 = 2(√2)/3 或 3x + 1 = -2(√2)/3
3x = (-3 + 2√2)/3 或 3x = (-3 - 2√2)/3
x = (-3 + 2√2)/9 或 x = (-3 - 2√2)/9
兩邊同時乘以 18 :
{[(3x + 1)²/2] - (1/3)} × 18 = (1/9) × 18
9(3x + 1)² - 6 = 2
9(3x + 1)² = 8
(3x + 1)² = 8/9
3x + 1 = √(8/9) 或 3x + 1 = -√(8/9)
3x + 1 = 2(√2)/3 或 3x + 1 = -2(√2)/3
3x = (-3 + 2√2)/3 或 3x = (-3 - 2√2)/3
x = (-3 + 2√2)/9 或 x = (-3 - 2√2)/9
收錄日期: 2021-04-18 14:31:45
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https://hk.answers.yahoo.com/question/index?qid=20160214013231AAmAYgx