✔ 最佳答案
Method 1:
|1 a b|
|a 1 b|
|a b 1|
=1*1*1 + a*b*a + b*a*b - b*1*a - a*a*1 - 1*b*b
= 1 + a²b + ab² - ab - a² - b²
= (1 - a²) + (a²b - ab) + (ab² - b²)
= (1 - a)(1 + a) + ab(a - 1) + b²(a - 1)
= - (a - 1)(1 + a) + (a - 1)(ab + b²)
= (a - 1) [ - (1 + a) + (ab + b²) ]
= (a - 1) (ab - a + b² - 1)
= (a - 1) [ a(b - 1) + (b - 1)(b + 1) ]
= (a - 1) (b - 1) (a + b + 1)
Method 2:
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