Physics question?

...
A
after collision
p = (M1 + M2) v = (0.01 + 0.19) (10) = 5.0 kg*m/s

B
momentum was conserved
5.0 kg*m/s

C
before
p = M1 V1
5.0 = 0.01 V1
V1 = 500 m/s

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A bullet of mass m = 0.01kg is fired into sandbag of mass M = 0.49kg hanging from a tree. The sandbag with the bullet embedded into it, swings away at v = 10m/s find

A.the momentum after collision

Pf = (m + M)v = .5*10 = 5 kg.m/s ANS.

B.the momentum before the collision

Same as A from the conservaton of momentum, i.e., Pi = Pf = 5 kg.m/s ANS.

C. The velocity of the bullet

v = Pi/m = 5/.01 = 50 m/s. ANS.