已知"#"為一個新的運算符號，且定一其運算規則為"a#b=-(a^2-b)/a"。 第一題:2#(-4)=? 第二題:(-3)#(-2)=? 求詳細解答 謝謝><?
回答 (2)
2016-02-09 11:04 am
✔ 最佳答案
a#b=-(a² - b)/a1.
2#(-4)
= -[2² - (-4)]/2
= -[4 + 4]/2
= -8/2
= -4
2.
(-3)#(-2)
= -[(-3)² - (-2)]/(-3)
= [9 + 2]/3
= 11/3
2016-02-09 2:26 pm
1.
2#(-4)
= -[2² - (-4)]/2
= -[4 + 4]/2
= -8/2
= -4
2.
(-3)#(-2)
= -[(-3)² - (-2)]/(-3)
= [9 + 2]/3
= 11/3
2#(-4)
= -[2² - (-4)]/2
= -[4 + 4]/2
= -8/2
= -4
2.
(-3)#(-2)
= -[(-3)² - (-2)]/(-3)
= [9 + 2]/3
= 11/3
收錄日期: 2021-04-18 14:23:27
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160209025534AAaiLpr