求x^+6x-y^-4y+5因式分解?
回答 (2)
2016-02-06 1:37 pm
✔ 最佳答案
Solx^2+6x－y^2－4y+5
=(x+6x)－(y^2+4y)+5
=(x^2+6x+9)－(y^2+4y+4)
=(x+3)^2－(y+2)^2
=(x+3－y－2)(x+3+y+2)
=(x-y+1)(x+y+5)
2016-02-07 2:01 am
x^2+6x－y^2－4y+5
=(x^2+6x)－(y^2+4y)+5
=(x^2+6x+9)－(y^2+4y+4)
=(x+3)^2－(y+2)^2
=(x+3－y－2)(x+3+y+2)
=(x-y+1)(x+y+5)
=(x^2+6x)－(y^2+4y)+5
=(x^2+6x+9)－(y^2+4y+4)
=(x+3)^2－(y+2)^2
=(x+3－y－2)(x+3+y+2)
=(x-y+1)(x+y+5)
收錄日期: 2021-04-18 14:28:02
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160206051900AAANFAO