Differentiate y= sin(4x)?
回答 (4)
2016-02-05 1:49 pm
*Chain Rule*
1. first differentiate the "4x"
then "replace" the 4x with... lets say "u"
so it's sin(u)
2. now differentiate sin(u)
which is cos(u) , replace the u with the "original" which is 4x
so final answer is: 4cos(4x)
1. first differentiate the "4x"
then "replace" the 4x with... lets say "u"
so it's sin(u)
2. now differentiate sin(u)
which is cos(u) , replace the u with the "original" which is 4x
so final answer is: 4cos(4x)
2016-02-05 4:19 pm
dy/dx = 4 cos (4x)
2016-02-05 1:45 pm
y = sin(4x)
dy/dx = cos(4x) d/dx (4x)
dy/dx = cos 4x (4)
dy/dx = 4 cos(4x)
dy/dx = cos(4x) d/dx (4x)
dy/dx = cos 4x (4)
dy/dx = 4 cos(4x)
2016-02-05 1:40 pm
y = sin(4x)
dy/dx
= d/dx sin(4x)
= cos(4x) d/dx 4x
= cos(4x) * 4
= 4cos(4x)
dy/dx
= d/dx sin(4x)
= cos(4x) d/dx 4x
= cos(4x) * 4
= 4cos(4x)
收錄日期: 2021-04-21 16:41:10
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160205053624AA5Pyif