find dy/dx when y= cos^4 x?
回答 (3)
2016-02-05 4:21 pm
y = [ cos x ]^4
dy/dx = - 4 cos³x sin x
dy/dx = - 4 cos³x sin x
2016-02-05 1:42 pm
y = cos^4 x
dy/dx = 4 cos^3 x d/dx ( cos x)
dy/dx = 4 cos^3 x ( -sin x)
dy/dx = -4 sin x cos^3 x
dy/dx = 4 cos^3 x d/dx ( cos x)
dy/dx = 4 cos^3 x ( -sin x)
dy/dx = -4 sin x cos^3 x
2016-02-05 1:35 pm
y = cos^4 (x)
dy/dx
= 4cos^3 (x) d/dx (cos(x))
= 4cos^3 (x) (-sin(x)
= -4 sin(x) cos^3 (x)
dy/dx
= 4cos^3 (x) d/dx (cos(x))
= 4cos^3 (x) (-sin(x)
= -4 sin(x) cos^3 (x)
收錄日期: 2021-04-21 16:40:10
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160205053135AAk5uXv