Please solve the following questions with solutions. Thanks?
回答 (2)
2016-02-10 10:18 am
10
∫x(x+1/x^2)dx
=∫x^2+1/xdx
=x^3/3+ln｜x｜+c
(C)
11
∫x^2(x^3+1)^5dx
=(1/3) ∫(x^3+1)^5dx^3
=(1/3) ∫(x^3+1)^5d(x^3+1)
=(1/18)(x^3+1)^6+c
(E)
12
∫e^√x/√xdx
Set y=x^(1/2)
dy=(1/2)x^(－1/2)dx
∫e^√x/√xdx
=2∫e^√x/(2√x)dx
=2∫e^ydy
=2e^y+c
=2e^√x+c
(B)
∫x(x+1/x^2)dx
=∫x^2+1/xdx
=x^3/3+ln｜x｜+c
(C)
11
∫x^2(x^3+1)^5dx
=(1/3) ∫(x^3+1)^5dx^3
=(1/3) ∫(x^3+1)^5d(x^3+1)
=(1/18)(x^3+1)^6+c
(E)
12
∫e^√x/√xdx
Set y=x^(1/2)
dy=(1/2)x^(－1/2)dx
∫e^√x/√xdx
=2∫e^√x/(2√x)dx
=2∫e^ydy
=2e^y+c
=2e^√x+c
(B)
2016-02-05 12:44 am
10
∫x(x+1/x^2)dx
=∫x^2+1/xdx
=x^3/3+ln｜x｜+c
(C)
11
∫x^2(x^3+1)^5dx
=(1/3) ∫(x^3+1)^5dx^3
==(1/3) ∫(x^3+1)^5d(x^3+1)
=(1/18)(x^3+1)^6+c
(E)
12
∫e^√x/√xdx
Set y=x^(1/2)
dy=(1/2)x^(－1/2)dx
∫e^√x/√xdx
=2∫e^√x/(2√x)dx
=2∫e^ydy
=2e^y+c
=2e^√x+c
(B)
∫x(x+1/x^2)dx
=∫x^2+1/xdx
=x^3/3+ln｜x｜+c
(C)
11
∫x^2(x^3+1)^5dx
=(1/3) ∫(x^3+1)^5dx^3
==(1/3) ∫(x^3+1)^5d(x^3+1)
=(1/18)(x^3+1)^6+c
(E)
12
∫e^√x/√xdx
Set y=x^(1/2)
dy=(1/2)x^(－1/2)dx
∫e^√x/√xdx
=2∫e^√x/(2√x)dx
=2∫e^ydy
=2e^y+c
=2e^√x+c
(B)
收錄日期: 2021-04-18 14:27:53
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160204101816AAS5CXb