更新1:
謝謝
請問如何求出(2/3)^x?
回答 (3)
2016-02-03 6:52 am
✔ 最佳答案
Sol2^(x+1)=3^(x+2)
2*2^x=9*3^x
2^x/3^x=9/2
(2/3)^x=9/2
2016-02-03 7:16 am
2^(x+1) = 3^(x+2)
2(2^x) = 9(3^x)
2^x / 3^x = 9/2
(2/3)^x = 9/2
2(2^x) = 9(3^x)
2^x / 3^x = 9/2
(2/3)^x = 9/2
2016-02-13 4:27 am
2^(x+1)=3^(x+2)
(2^x)/(3^x)=9/2
(2/3)^x=9/2
(2^x)/(3^x)=9/2
(2/3)^x=9/2
收錄日期: 2021-04-18 14:24:43
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160202221313AA9Higa