Math Question. With Solution. Thanks?

f(x) = sin(πx)

f ’ (x) = π cos(πx)

f ” (x) = －π² sin(πx)

f ” (1/2) =－π² sin(π/2) = －π^2

Answer (D)

Sol
f(x)=Sin(πx)
f’(x)=df(x)/dx=dSin(πx)/d(πx)*π=πCos(πx)
f”(x)=df’(x)/dx=πdCos(πx)/dx=－π^2Sin(πx)
f”(1/2)=－π^2Sin(π/2)=—π^2
(D