please help me factor this equation 64a^6n-b^6n?
回答 (2)
2016-02-01 2:35 pm
Presuming that is:
64a⁶ⁿ - b⁶ⁿ
Then you have a difference of two squares:
(8a³ⁿ + b³ⁿ)(8a³ⁿ - b³ⁿ)
Now we have the sum and difference of two cubes, so each can be factored further:
(2aⁿ + bⁿ)(4a²ⁿ - 2aⁿbⁿ + b²ⁿ)(2aⁿ - bⁿ)(4a²ⁿ + 2aⁿbⁿ + b²ⁿ)
64a⁶ⁿ - b⁶ⁿ
Then you have a difference of two squares:
(8a³ⁿ + b³ⁿ)(8a³ⁿ - b³ⁿ)
Now we have the sum and difference of two cubes, so each can be factored further:
(2aⁿ + bⁿ)(4a²ⁿ - 2aⁿbⁿ + b²ⁿ)(2aⁿ - bⁿ)(4a²ⁿ + 2aⁿbⁿ + b²ⁿ)
2016-02-01 2:30 pm
收錄日期: 2021-04-21 16:37:00
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https://hk.answers.yahoo.com/question/index?qid=20160201062654AA3SPYa