Math Question. With full solution. Thanks?

f ’ (x) = 4x³－3x² + 2
f(x) = x⁴－x³ + 2x + C
f(0) = 0－0 + 0 + C = 5
C = 5

f(x) = x⁴－x³ + 2x + 5
f(1) = 1－1 + 2 + 5 = 7

Answer (E)

Sol
f’(x)=4x^3－3x^2+2
f(x)=x^4－x^3+2x+c
f(0)=0－0+0+c=5
c=5
f(x)=x^4－x^3+2x+5
f(1)=1－1+2+5=7
(E)