圖中第30,31,32,33題怎樣做？ 請詳細說明?
回答 (2)
2016-01-13 12:31 pm
30
√3[√(6)+2√(27)+√(15)]
=√3[√(2*3)+2*3√(3)+√(3*5)]
=3[(√2)+6+√(5)]
=18+3√2+3√5
31
(√11－√5)(√11+√5)
=11－5
=6
32
(√7+3√2)^2
=7+6√14+18
=25+6√14
33
(4√2+√3)(3√3－√2)
=12√6－8+9－√6
=1+11√6
√3[√(6)+2√(27)+√(15)]
=√3[√(2*3)+2*3√(3)+√(3*5)]
=3[(√2)+6+√(5)]
=18+3√2+3√5
31
(√11－√5)(√11+√5)
=11－5
=6
32
(√7+3√2)^2
=7+6√14+18
=25+6√14
33
(4√2+√3)(3√3－√2)
=12√6－8+9－√6
=1+11√6
2016-01-13 8:12 am
30
Sol
√3(√6+2√27+√15)
=√18+2√81+√45
=3√2+2*9+3√5
=18+3√2+3√5
31
Sol
(√11－√5)(√11+√5)
=11－5
=6
32
Sol
(√7+3√2)^2
=(√7)^2+2*√7*(3√2)+(3√2)^2
=7+6√14+18
=25+6√14
33
Sol
(4√2+√3)(3√3－√2)
=(4√2)*(3√3)－(4√2)*√2+√3*3√3－√3*√2
=12√6－8+9－√6
=1+11√6
Sol
√3(√6+2√27+√15)
=√18+2√81+√45
=3√2+2*9+3√5
=18+3√2+3√5
31
Sol
(√11－√5)(√11+√5)
=11－5
=6
32
Sol
(√7+3√2)^2
=(√7)^2+2*√7*(3√2)+(3√2)^2
=7+6√14+18
=25+6√14
33
Sol
(4√2+√3)(3√3－√2)
=(4√2)*(3√3)－(4√2)*√2+√3*3√3－√3*√2
=12√6－8+9－√6
=1+11√6
收錄日期: 2021-04-18 14:17:43
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160112173745AAZaTyQ