A gas is 65.8 L at 129 kPa. What volume would the gas be at 76.2 kPa?
回答 (2)
2016-01-11 7:54 pm
(65.8 L) x (129 kPa / 76.2 kPa) = 111 L
2016-01-11 10:43 am
P1 = 129 kPa
V1 = 65.8 L
P2 = 76.2 kPa
V2 = ?
According to Boyle's law :
P1 V1 = P2 V2
129 × 65.8 = 76.2 V2
Volume, V2 = 0.111 L
V1 = 65.8 L
P2 = 76.2 kPa
V2 = ?
According to Boyle's law :
P1 V1 = P2 V2
129 × 65.8 = 76.2 V2
Volume, V2 = 0.111 L
收錄日期: 2021-04-18 14:18:10
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