What is the total potential energy of this system?

2016-01-10 10:32 am
Only the balls have mass:
m - small mass
M - large mass
The beam they are attached to have no mass. The beam can rotate all the way around the axis attached to the supporting beam at the middle. The distance from the axis to the mass are the same length.

There is gravity which points dawn on the picture.
See the picture for a sketch of the system.

回答 (5)

2016-01-10 1:19 pm
Ep = g(M*h1+m*h2)
2016-01-10 11:17 am
The system described is labil, the big mass will fall down and the small one will rise.
They will at last rest with the big mass at the bottom after a fall of l/2 where l is the length of the beam to which they are fastened.
The Potential energy gained of the big mass is Mg*l/2 - mg*i/2. The lifting of the small mass is a loss of energy for the fall of the big mass.
2016-01-10 11:12 am
The question is unclear. The only form of potential energy to consider appears to be gravitational potential energy.

If:
- the system is on the earth;
- the local value of gravitational field strength (acceleration due to gravity) is g (g is typically 9.8m/s² downwards);
- we take ground level as zero potential energy;
then the total gravitational potential energy is MgH + mgh where H and h respectively are the heights of M and m above the ground.
2016-01-10 11:01 am
"See the picture for a sketch of the system"
Where is the picture?
2016-01-10 10:32 am
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