（2x-1）（3x+1）＝4 （公式法怎么解？）?
回答 (1)
2016-01-13 11:33 pm
0 = 6x^2 - 3x +2x - 1 - 4
= 6x^2 - x - 5
= (6x+5)(x-1)
x = 1 or -5/6
= 6x^2 - x - 5
= (6x+5)(x-1)
x = 1 or -5/6
收錄日期: 2021-05-01 15:26:17
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