The amount of a certain radioactive substance remaining after t years is given by a function of the form Q(t)=Qe^-0.003t.Find the half-life of the substance.
Q(t)=Qe^-0.003t
but Q(t) is also
Q(t)=Q*2^(-t/L)
where L=half life
so equate
Q*2^(-t/L)=Qe^(-0.003t)
cancel Q and take ln
(-t/L)(ln(2)=-0.0003t
cancel -t and solve for L
L=ln(2)/0.0003
=(10000/3)(ln(2))