我想這類應該用甚麼方法計算?
1.m=abc/a-b,then b=
2.x+a/x-a=2/3,then x=
3.if x = -5 is the solution of the equation kx-7= 17+k,then x =
數學方程問題,要解釋,不求答案?
2016-01-06 8:09 am
回答 (2)
2016-01-06 9:25 am
✔ 最佳答案
1.m = abc / ( a - b )
ma - mb = abc
ma = mb + abc = b( m + ac )
b = ma / ( m + ac ) ..... Ans
2.
(x+a) / (x-a) = 2 / 3
2(x-a) = 3(x+a)
2x - 2a = 3x + 3a
x = - 5a ..... Ans
3.
( 這題應該是要求 k , 而不是求 x )
Sol :
x = - 5 為此方程式之解, 故可滿足此方程式:
k( - 5 ) - 7 = 17 + k
- 5 k - 7 = 17 + k
6k = - 24
k = - 4 ..... Ans
2016-01-06 10:20 am
1.
m = abc / ( a - b )
ma - mb = abc
ma = mb + abc = b( m + ac )
b = ma / ( m + ac )
2.
(x+a) / (x-a) = 2 / 3
2(x-a) = 3(x+a)
2x - 2a = 3x + 3a
x = - 5a
3.
( 這題應該是要求 k , 而不是求 x )
x = - 5 為此方程式之解, 故可滿足此方程式:
k( - 5 ) - 7 = 17 + k
- 5 k - 7 = 17 + k
6k = - 24
k = - 4
m = abc / ( a - b )
ma - mb = abc
ma = mb + abc = b( m + ac )
b = ma / ( m + ac )
2.
(x+a) / (x-a) = 2 / 3
2(x-a) = 3(x+a)
2x - 2a = 3x + 3a
x = - 5a
3.
( 這題應該是要求 k , 而不是求 x )
x = - 5 為此方程式之解, 故可滿足此方程式:
k( - 5 ) - 7 = 17 + k
- 5 k - 7 = 17 + k
6k = - 24
k = - 4
收錄日期: 2021-04-18 14:18:26
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