方程問題 1/3 x ( h-4)^2 x h = 1/2 x 4/3(h-4)^3 請問呢條點做 ?
回答 (1)
2016-01-05 2:24 am
1/3 x (h - 4)^2 x h = 1/2 x 4/3 x (h - 4)^3
h(h - 4)^2 = 2(h - 4)^3
2(h - 4)^3 - h(h - 4)^2 = 0
(h - 4)^2 [2(h - 4) - h] = 0
(h - 4)^2 (h - 8) = 0
(h - 4)^2 = 0 或 h - 8 = 0
h = 4 或 h = 8
h(h - 4)^2 = 2(h - 4)^3
2(h - 4)^3 - h(h - 4)^2 = 0
(h - 4)^2 [2(h - 4) - h] = 0
(h - 4)^2 (h - 8) = 0
(h - 4)^2 = 0 或 h - 8 = 0
h = 4 或 h = 8
收錄日期: 2021-04-18 14:22:25
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160104181751AAyT4Vk