急!!!對數函數問題，請問怎麼解答?

1.
log2(x)+log8(x)=2log2(x)*log8(x)
use base conversion, log8(x)=log(2^3)(x)=log2(x)/3
log2(x)+log2(x)/3=(2/3)log2(x)*log2(x)
log2(x)^2-2log2(x)=0
log2(x)[log2(x)-2]=0
log2(x)=0, or log2(x)=2
x=1 or x=2^2=4

2.
3^(2x+1)=2^(x-3)
take log on both sides
(2x+1)/log(3) = (x-3)/log(2)
Cross multiply and solve for x
log(2)(2x+1)=log(3)(x-3)
x=(3log(3)+log(2))/[log(3)-2log(2)]
=-13.86595

1.
(log x)/(log 2)+(log x)/(3log 2)=2(log x)(logx)/[3(log 2)(log 2)]
3(log x)+(log x)=2(log x)(log x)/(log 2)
2(log x)=(log x)(log x)/log 2
(log x)(log x/log 2 -2)=0
log x=0 or log x=2log2
x=1 or x=4

2.
(2x+1)log 3=(x-3)log 2
(2log 3)x +log 3=(log 2)x -3log 2
(2log 3 -log 2)x=-3log2 -log3
(log 2-log9)x=log 8+log 3
x=-2.112958972