求ｎ？方程問題　唔識計！?

你是否想解
(1 - (1+0.06)ⁿ⁻¹) / ((1 - (1+0.06)) = 4
(1 - (1+0.06)ⁿ⁻¹) / (- 0.06) = 4
1 - (1+0.06)ⁿ⁻¹ = 4(- 0.06)
1 - 1.06ⁿ⁻¹ = - 0.24
1.06ⁿ⁻¹ = 1.24
log 1.06ⁿ⁻¹ = log 1.24
(n - 1) log 1.06 = log 1.24
n - 1 = log 1.24 / log 1.06
n = (log 1.24 / log 1.06) + 1
n = 4.6917

原式
(1 - (1+0.06)ⁿ⁻¹) / 0.06 = 4
1 - (1+0.06)ⁿ⁻¹ = 4(0.06)
1 - (1.06)ⁿ⁻¹ = 0.24
(1.06)ⁿ⁻¹ = 1 - 0.24
(1.06)ⁿ⁻¹ = 0.76
log (1.06)ⁿ⁻¹ = log 0.76
(n - 1) log 1.06 = log 0.76
n - 1 = log 0.76 / log 1.06
n = (log 0.76 / log 1.06) + 1 = - 3.709833332

本人更正
a^n=b iff n=log b / log a 其中 a,b 不小於 0, 你可想為何。
如果你想求n,
-(4+1/0.06-1) 不等於 (1+1.06)^n
故n沒有解
"唔識計"? 當然"唔識計" 因為n沒有解。

(可能抄錯了題目, 可能導師出錯)

你是否想解
(1 - (1+0.06)ⁿ⁻¹) / ((1 - (1+0.06)) = 4
(1 - (1+0.06)ⁿ⁻¹) / (- 0.06) = 4
1 - (1+0.06)ⁿ⁻¹ = 4(- 0.06)
1 - 1.06ⁿ⁻¹ = - 0.24
1.06ⁿ⁻¹ = 1.24
log 1.06ⁿ⁻¹ = log 1.24
(n - 1) log 1.06 = log 1.24
n - 1 = log 1.24 / log 1.06
n = (log 1.24 / log 1.06) + 1
n = 4.6917

原式
(1 - (1+0.06)ⁿ⁻¹) / 0.06 = 4
1 - (1+0.06)ⁿ⁻¹ = 4(0.06)
1 - (1.06)ⁿ⁻¹ = 0.24
(1.06)ⁿ⁻¹ = 1 - 0.24
(1.06)ⁿ⁻¹ = 0.76
log (1.06)ⁿ⁻¹ = log 0.76
(n - 1) log 1.06 = log 0.76
n - 1 = log 0.76 / log 1.06
n = (log 0.76 / log 1.06) + 1 = - 3.709833332