It is given that z=(3m+2)+(m-4)i, where m is real number and i^2=-1.If z is a real number, find the value of m.?
回答 (3)
✔ 最佳答案
If z is a real number
Let's
(m-4)i=0i
m=4
z = (3m + 2) + (m - 4)i
If z is a real number, the imaginary part of z should be zero, i.e.
(m - 4)i = 0
m - 4 = 0
m = 4
how about this part(3m + 2)
收錄日期: 2021-04-18 14:14:28
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