3x = 2y-2
5x = 2y+2
How to solve this system of equations?
2015-12-21 9:30 pm
回答 (5)
2015-12-21 9:35 pm
Since they both contain 2y you immediately have
3x + 2 = 5x - 2
x = 2
y = (3*2 + 2)/2 = 4
3x + 2 = 5x - 2
x = 2
y = (3*2 + 2)/2 = 4
2015-12-21 9:34 pm
3x = 2y - 2
5x = 2y + 2
solve for "2y," then substitute...
2y = 3x + 2
5x = 3x + 2 + 2
2x = 4
x = 2
can you find y ? Why not ? check your results !!
[(2, 4) ]
5x = 2y + 2
solve for "2y," then substitute...
2y = 3x + 2
5x = 3x + 2 + 2
2x = 4
x = 2
can you find y ? Why not ? check your results !!
[(2, 4) ]
2015-12-21 11:01 pm
3x - 2y = - 2
-5x + 2y = -2_____ADD
-2x = - 4
x = 2
2y = 8
y = 4
x = 2 , y = 4
-5x + 2y = -2_____ADD
-2x = - 4
x = 2
2y = 8
y = 4
x = 2 , y = 4
2015-12-21 9:43 pm
3x = 2y-2
5x = 2y+2
2x=4 // subtract eq
x=2
3(2)=2y-2 // substitute
2y=8
y=4
5x = 2y+2
2x=4 // subtract eq
x=2
3(2)=2y-2 // substitute
2y=8
y=4
2015-12-21 9:36 pm
I couldn't figure out the formatting on here so I took a screenshot on notepad https://s.yimg.com/hd/answers/i/fa7f399b1c4c4fa586f23ab58a3e5819_C.png?a=answers&mr=0&x=1450741191&s=fcd860cd8a96d9f9be5a61c8679a90ae
收錄日期: 2021-04-21 15:58:48
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151221133025AADZUQW