更新1:
6 & 7 have to be in fraction form.
Math Probability Question 4 (help me please! LAST ONE, I PROMISE!!!)?
回答 (3)
2015-12-21 4:05 am
✔ 最佳答案
21/26 have at least one pet0 have all three
2015-12-21 4:00 am
You should be able to figure out such an easy problem. You need to try harder and not give up and turn to us so fast.
You add up all the numbers and get n. Notice that 5 have no pet. The answer is (n-5)/n.
Then you divide the number who have all 3 pets by n.
You add up all the numbers and get n. Notice that 5 have no pet. The answer is (n-5)/n.
Then you divide the number who have all 3 pets by n.
2015-12-21 3:14 am
6)100%. at least 1 guy has a pet
7) 0%. no one has 3 pets
7) 0%. no one has 3 pets
收錄日期: 2021-04-21 16:02:24
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