導函數問題 求f'(x) f(x)=2x sin2x+cos2x?
回答 (2)
2015-12-24 8:28 am
✔ 最佳答案
f(x) = 2x sin2x+cos2xf'(x) = 2sin2x+4xcos2x-2sin2x
= 4xcos2x
2015-12-20 1:22 pm
Sol
f(x)=2xSin2x+Cos2x
f’(x)=2x*dSin2x/d(2x)+2Sin2x+2*dCos2x/d(2x)
=2xCos2x+2Sin2x－2Sin2x
=2xCos2x
f(x)=2xSin2x+Cos2x
f’(x)=2x*dSin2x/d(2x)+2Sin2x+2*dCos2x/d(2x)
=2xCos2x+2Sin2x－2Sin2x
=2xCos2x
收錄日期: 2021-04-30 20:26:07
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151220040632AAMqlvi