Dynamics Homework!
An aircraft lands and deploys a drag parachute. This causes an acceleration on the plane of a=-Zv^2?
An aircraft lands and deploys a drag parachute. This causes an acceleration on the plane of
a= -Z v^2
(Z=0.0045 is a constant given below and v is instantaneous velocity)
You are required to calculate
The time required for the aircraft to slow from 80 to 5 m/s.
The distance covered during this change in velocity
For part i) use the fact that a= dv/dt
Equate this to the expression for acceleration (1 mark), separate variables, (2 marks) integrate between appropriate limits (4 marks) to obtain an expression for t , the time.(1 mark). Solve (2 marks)
For part ii) use the fact that a= dv/dt = dv/ds ds/dt =v dv/ds
Again integrate between appropriate limits to obtain an expression for s , the distance travelled
回答 (2)
✔ 最佳答案
(i) a = dv/dt = -z*v^2
∫(80~5)dv/v^2 = -z∫(0~t)dt
z*t = 1/v
t = (1/5 - 1/80)/0.0045
= 15/80*0.0045
= 3/16*0.0045
= 3/0.0072
= 41.6667 sec
(ii) a= dv/dt
= dv/ds * ds/dt
= v * dv/ds
= -z*v^2
0.5∫(80~5)d(v^2)/v^2 = -z∫(0~s)ds
0.5*ln(v^2) = -z*s
s = 1/2z * ln(80/5)
= 1/0.009 * ln(16)
= 111.111 * 4 * ln(2)
= 444.444 * 0.693
= 308 meters
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收錄日期: 2021-05-01 15:38:15
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