如下圖所示，若簡支梁之截面寬為 100 mm，高為 200 mm，則梁中點處之中立軸上方 1 cm 之彎曲應力為多少 MPa？ 請問詳解 謝謝?
回答 (1)
2015-12-16 11:21 am
✔ 最佳答案
梁截面寬b=0.1m，高h=0.2m，梁中點中立軸上方y=0.01m, St = ? MPaI = bh^3/12
= 0.1*0.2^3/12
= 6.667*10^-5 m^4
M = R * L/2
= 50 kN * 3 m
= 150 kN.m
= 15*10^4 N.m
St = M*y/I
= 15*10^4 * 0.01 / 6.6667*10^-5
= 225*10^5 N/m^2
= 22.5 MPa
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151216001919AAYkd9G