coulomb’s law?
Two point charges q1 and q2 are 3m apart, and their combined charge is 40 μC.
(a) If one repels the other with a force of 0.175 N, what are the two charges?
(b) If one attracts the other with a force of 0.225 N, what are the two charges?
回答 (1)
Coulomb's law
Two charges q1 and q2 are 3m apart, q1 + q2 = 40 μC = a
(a) If one repels the other with F1 = 0.175 N, q1,q2 = ??
q2 = a - q1
F1 = k*q1*(a - q1) / r^2
0 = k*q1^2 - a*k*q1 + F1*r^2
q1 = {a*k + - √[(a*k)^2 - 4k*F1*r^2]} / 2k
= {40*10^-6 + - √[(40*9000)^2 - 4*9*10^9*0.175*9]}/2*9*10^9
= {35 μC; 5 μC}
q2 = a - q1
= {5 μC; 35 μC} ;;; Same Poarity
(b) If one attracts the other with a force of 0.225 N, what are the two
charges?
q1 = {a*k + - √[(a*k)^2 - 4k*F2*r^2]} / 2k
= {40*10^-6 + - √[(40*9000)^2 - 4*9*10^9*0.225*9]}/2*9*10^9
= {33.23 μC; 6.77 μC}
q2 = a - q1
= {6.77 μC; 33.23 μC} ;;; Opposite Poarity
收錄日期: 2021-05-01 15:25:00
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