Solve the simultaneous equations : 1/4 Ω x = 4 3 Ω 2x = y 請幫忙, 謝謝?

Not too sure if the symbol Ω is meant to be exponent ^.
Following solution assumes the equation to be:
(1/4)^x=4(3^(2x))=y
If it is not the case, you can solve in a similar way.

First solve
(1/4)^x=4(3^(2x))
take (natural) log on both sides
x*log(1/2)=(2x)*log(3)+log(4)
isolate x:
x(log(1/2)-2log(3))=log(4)
x=log(4)/(log(1/2)-2log(3))
Evaluating right-hand side,
x=-0.3868528 approx.
check: (1/4)^x-4(3^(2x))=0, ok.
hence
y=(1/4)^x=(1/4)^-0.3868528=1.70966 approx.