1/S^3(S-3)}部分分式分解，求解?
回答 (1)
2015-12-13 9:54 am
￡{1/(s-3)s^3}
= ￡{-1/27s - 1/9s^2 - 1/3s^3 + 1/27(s-3)} ;;; Note
= -1/27 - t/9 - t^2/6 + e^3t/27
Note:
1/1/(s-3)s^3 = a/s + b/s^2 + c/s^3 + d/(s-3)
f(s) = 1 = a(s-3)s^2 + bs(s-3) + c(s-3) + ds^3
f(0) = 1 = -c ==> c = -1/3
f(3) = 1 = 27d ==> d = 1/27
s^3 term: 0 = a + d ==> a = -1/27
s term: 0 = -3b + c ==> b = 1/9
= ￡{-1/27s - 1/9s^2 - 1/3s^3 + 1/27(s-3)} ;;; Note
= -1/27 - t/9 - t^2/6 + e^3t/27
Note:
1/1/(s-3)s^3 = a/s + b/s^2 + c/s^3 + d/(s-3)
f(s) = 1 = a(s-3)s^2 + bs(s-3) + c(s-3) + ds^3
f(0) = 1 = -c ==> c = -1/3
f(3) = 1 = 27d ==> d = 1/27
s^3 term: 0 = a + d ==> a = -1/27
s term: 0 = -3b + c ==> b = 1/9
收錄日期: 2021-04-30 20:19:19
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151212191417AAyY0ci