A simple harmonic oscillator has an amplitude of 3.50 cm and a maximum speed of 23 cm/s. What is its speed when the displacement is 1.75 cm?
A simple harmonic oscillator has an amplitude of 3.50 cm and a maximum speed of 23 cm/s. What is its speed when the displacement is 1.75 cm?
11.5 cm/s
21.8 cm/s
19.9 cm/s
16.3 cm/s
Physics Help. Answer please?
2015-12-10 4:53 pm
回答 (1)
2015-12-10 11:01 pm
✔ 最佳答案
1.75 cm is ½ of the amplitude.The spring energy there is ¼ of the maximum.
Therefore the KE there is 3/4 of the maximum.
Therefore the velocity is √(3/4) of the maximum, or
v = 23cm/s * √0.75 = 19.9 cm/s
Hope this helps!
收錄日期: 2021-04-21 15:40:13
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