A 0.500-kg mass on a spring has velocity as a function of time given by vx(t)=(3.60cm/s)sin[(4.71s−1)t−π/2].
What is the period?
What is the amplitude?
What is the maximum acceleration of the mass?
What is the force constant of the spring?
Physics Help. Answer please?
2015-12-10 4:50 pm
回答 (1)
2015-12-10 11:08 pm
✔ 最佳答案
The coefficient of "t" in the trig argument is equal to 2π / Twhere T is the period. so
4.71/s = 2π/T
T = 1.33 s ◄ period
The coefficient of the trig argument in the velocity equation is the amplitude times the coefficient of "t", so
3.60cm/s = A * 4.71/s
A = 0.764 cm ◄ amplitude
max acceleration = A * (2π/T)² = 0.764cm * (4.71/s)² = 17.0 cm/s² ◄
k = m*(2π/T)² = 0.500kg * (4.71/s)² = 11.1 kg/s² = 11.1 N/m ◄ stiffness
Hope this helps!
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