4a^4+1的因式分解該如何解，求詳細過程。?
回答 (2)
2015-12-10 4:14 pm
✔ 最佳答案
4a⁴+ 1= (4a⁴+ 4a² + 1) - 4a²
= (2a² + 1)² - (2a)²
= (2a² - 2a + 1) (2a² + 2a+ 1)
2016-01-05 11:22 am
4a⁴+ 1
= (4a⁴+ 4a² + 1) - 4a²
= (2a² + 1)² - (2a)²
= (2a² - 2a + 1) (2a² + 2a+ 1)
= (4a⁴+ 4a² + 1) - 4a²
= (2a² + 1)² - (2a)²
= (2a² - 2a + 1) (2a² + 2a+ 1)
收錄日期: 2021-04-18 14:10:46
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151210063614AALEL69