What is the volume occupied by 21.6 g of argon gas at a pressure of 1.38 atm and a temperature of 389 K ?
回答 (1)
2015-12-08 10:07 am
Molar mass Ar = 39.95g/mol
Mol Ar in 21.6g = 21.6/39.95 = 0.541mol
Calculate volume using gas equation:
PV = nRT
1.38*V = 0.541 * 0.082057*389
V = 0.541 * 0.082057*389 / 1.38
V = 12.5L
Mol Ar in 21.6g = 21.6/39.95 = 0.541mol
Calculate volume using gas equation:
PV = nRT
1.38*V = 0.541 * 0.082057*389
V = 0.541 * 0.082057*389 / 1.38
V = 12.5L
收錄日期: 2021-04-21 15:36:06
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https://hk.answers.yahoo.com/question/index?qid=20151207211108AALGSmA