limit of function?

2015-12-06 10:50 am
find the limit of lim x->infinity (e^x+1)^(-2/x)

回答 (1)

2015-12-06 10:59 am
✔ 最佳答案
y = lim (x->infinity) (e^x+1)^(-2/x)

ln(y) = (-2/x)*ln(e^x+1)

≒ -2/x * ln(e^x)

= -2/x * x

= -2


y = e^(-2)

= 1/e^2

= Answer


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