因式分解 x^4-10x^3+22x^2+10x+1 ，3Q~?
回答 (2)
2015-12-05 6:07 pm
✔ 最佳答案
x⁴-10x³+22x²+10x+1=x⁴-10x³+24x²+10x+1-2x² (用雙十字交乘)
x² -6x -1
x² -4x -1
=(x²-6x-1)(x²-4x-1)
2015-12-27 9:08 am
x⁴-10x³+22x²+10x+1
=x⁴-10x³+24x²+10x+1-2x² (用雙十字交乘)
x² -6x -1
x² -4x -1
=(x²-6x-1)(x²-4x-1)
=x⁴-10x³+24x²+10x+1-2x² (用雙十字交乘)
x² -6x -1
x² -4x -1
=(x²-6x-1)(x²-4x-1)
收錄日期: 2021-04-18 14:10:07
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151205085002AAI3zXV