Help me with problem number 20? Thank u guys.?
回答 (2)
2015-12-06 9:53 am
✔ 最佳答案
(2n+1) / [ n^2 * (n+1)^2 ] = 1/n^2 - 1/(n+1)^23/4 + 5/36 + ......... + (2n+1)/[ n^2*(n+1)^2 ]
= 1/1^2 - 1/2^2 + 1/2^2 - 1/3^2 + ......... + 1/n^2 - 1/(n+1)^2
= 1/1^2 - 1/(n+1)^2
= 1 - 1/(n+1)^2
as n → ∞
the series converges to 1
Ans: 1
2015-12-07 2:52 pm
Thank u thank u thank u very much.
收錄日期: 2021-05-02 14:09:19
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151204130547AAGCSOa