v=1.5-2.8y
t=0時流線=????
更新1:
有人知道嗎?
流體力學,求流線函數?
回答 (1)
2015-12-05 9:23 pm
u = 1.3 + 2.8x
v = 1.5 - 2.8y
Stream lines: dx/u = dy/v
dx/(1.3 + 2.8x) = dy/(1.5 - 2.8y)
1/2.8* ln(c) = ∫dx/(1.3 + 2.8x) + ∫dy/(-1.5 + 2.8y)
= 1/2.8 * ln(1.3 + 2.8x) + 1/2.8 * ln(-1.5 + 2.8y)
c = (1.3 + 2.8x)(-1.5 + 2.8y)
7.84xy + 2.8(1.3y - 1.5x) - 1.95 - c = 0
Set k = 1.95 + c = Arbitrary constants
Answer: 7.84xy + 2.8*(1.3y - 1.5x) = k
v = 1.5 - 2.8y
Stream lines: dx/u = dy/v
dx/(1.3 + 2.8x) = dy/(1.5 - 2.8y)
1/2.8* ln(c) = ∫dx/(1.3 + 2.8x) + ∫dy/(-1.5 + 2.8y)
= 1/2.8 * ln(1.3 + 2.8x) + 1/2.8 * ln(-1.5 + 2.8y)
c = (1.3 + 2.8x)(-1.5 + 2.8y)
7.84xy + 2.8(1.3y - 1.5x) - 1.95 - c = 0
Set k = 1.95 + c = Arbitrary constants
Answer: 7.84xy + 2.8*(1.3y - 1.5x) = k
收錄日期: 2021-05-01 15:39:33
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151203170049AAhiVL6